Question

Find the inverse of the function. y= oot(3)(x-2) Write your answer in the form a(bx+c)³+d, where a, b, c, and d are constants.

Answer 1

The inverse function of y = root(3)(x-2) is y = (x³) + 2 or in the form a(bx+c)³+d, it would be 1*(x³) + 2.

Step-by-step explanation:

The given function is

y = root(3)(x-2) To find the inverse of a function, we first rewrite the function in terms of x. That means we swap the roles of x and y, which gives us

x = root(3)(y-2) We then solve this new function for y, which gives us y = (x³) + 2 The inverse function of y = root(3)(x-2) is therefore y = (x³) + 2 or in the form of a(bx+c)³+d, is 1*(x³) + 2

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