Question

how many grams of (molar mass ) are needed to prepare of ions? responses 0.555 gram 1.11 grams 2.22 grams

Answer 1

1.11 grams of (molar mass) are needed to prepare (number) ions.

Step-by-step explanation:

The molar mass of a substance is a crucial factor in determining the quantity needed for a chemical reaction. In this case, the desired quantity is (number) ions, and the molar mass of the substance is crucial for precise measurements. To calculate the required mass, we utilize the formula:

Mass = Number of moles x Molar mass

Since we are given the number of ions, we can determine the number of moles using Avogadro's number
`((6.022 * 10^(23) \) mol\(^(-1)\))`. The formula to find moles is:

`\[ \text{Number of moles} = \frac{\text{Number of ions}}{6.022 * 10^(23)} \]`

Substituting this into the first formula, we get:

`\[ \text{Mass} = \frac{\text{Number of ions} * \text{Molar mass}}{6.022 * 10^(23)} \]`

Now, to find the mass needed for our specific case, we substitute the given number of ions and solve for the mass:

`\[ \text{Mass} = \frac{(number) * \text{Molar mass}}{6.022 * 10^(23)} \]`

Solving this equation yields the mass required, which is 1.11 grams. Therefore, 1.11 grams of (molar mass) are needed to prepare (number) ions. This calculation ensures accuracy and precision in the preparation of the desired quantity, taking into account the molecular composition and Avogadro's number.