To fill the cards and reach a final result of 1, let's solve the fraction path step by step:
1. Start with the fraction ⅚. We need to subtract a fraction to get 1/12. To do this, we subtract 1/12 from ⅚:
⅚ - 1/12 = (6/6) - (1/12) = 72/72 - 6/72 = 66/72
2. Next, we add 3/8 to the result obtained in step 1. This will give us the fraction that will be multiplied with an unknown fraction to get 11/46:
66/72 + 3/8 = 88/96 + 27/96 = 115/96
3. Now, we need to find the value of the unknown fraction that, when multiplied by 115/96, will give us 11/46. To solve for this fraction, we can cross-multiply and solve for the numerator:
(115/96) × (numerator/1) = 11/46
Cross-multiplying gives us: (115 × numerator) = (96 × 11)
Solving for the numerator: numerator = (96 × 11) / 115 = 9.4087
4. Moving on to the next card, we need to divide 11/46 by an unknown fraction to get 11/16. To solve for this fraction, we can set up a division equation:
(11/46) ÷ (unknown fraction) = 11/16
Cross-multiplying gives us: (11 × 16) = (46 × unknown fraction)
Solving for the unknown fraction: unknown fraction = (11 × 16) / 46 = 3.8261
5. Now, we need to add an unknown fraction to 11/16 to get 11/24. To find this fraction, we can subtract 11/16 from 11/24:
11/24 - 11/16 = (11 × 2) / (24 × 2) - (11 × 3) / (16 × 3)
Simplifying gives us: 22/48 - 33/48 = -11/48
6. Moving forward, we need to multiply 11/24 by an unknown fraction to get 11/36. To solve for this fraction, we can set up a multiplication equation:
(11/24) × (unknown fraction) = 11/36
Cross-multiplying gives us: (11 × 36) = (24 × unknown fraction)
Solving for the unknown fraction: unknown fraction = (11 × 36) / 24 = 16.5
7. Finally, we need to divide 11/36 by an unknown fraction to get 1. To find this fraction, we can set up a division equation:
(11/36) ÷ (unknown fraction) = 1
Cross-multiplying gives us: (11 × 1) = (36 × unknown fraction)
Solving for the unknown fraction: unknown fraction = (11 × 1) / 36 = 0.3056
By filling the cards with the respective fractions obtained in each step, following the indicated operations, we can achieve a path where the end result is 1.