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DE is drawn parallel to the base BC of a △ ABC, meeting AB at D and AC at E,ACAB=4 and CE=2 cm, find AE.

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Final answer:

To find the length of AE, we can use the property of similar triangles. By setting up a proportion using the given information, we can solve for AE.

Step-by-step explanation:

DE is drawn parallel to the base BC of triangle ABC and meets AB at D and AC at E. Given that AC/AB = 4 and CE = 2 cm, we need to find the length of AE.

Since DE is parallel to BC, we can use the property of similar triangles to solve this problem. Since AB = 4AC, we can write the proportion: AE/EC = AB/BC = 4/1. Substituting the given values, we have AE/2 = 4/1, which simplifies to AE = 8 cm.