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A block of cheese with a mass of 1.1 kg sits on a freshly waxed, essentially frictionless table. When a constant horizontal force of 0.50 N is applied to the cheese, which three external forces act on the cheese? a) Gravitational force, applied force, normal force b) Tension force, frictional force, normal force c) Gravitational force, frictional force, applied force d) Tension force, normal force, applied force

User MMG
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Answer:Option a) Gravitational force, applied force, normal force.

Step-by-step explanation:

When a constant horizontal force of 0.50 N is applied to the cheese, three external forces act on the cheese. These forces are:

a) Gravitational force: This force is always present and acts vertically downward. It is the force exerted by the Earth on the cheese due to gravity. In this case, it would be the weight of the cheese, which can be calculated by multiplying the mass (1.1 kg) by the acceleration due to gravity (9.8 m/s^2).

b) Applied force: This is the horizontal force of 0.50 N that is applied to the cheese. It is the force exerted on the cheese by an external source, such as a person pushing or pulling it.

c) Normal force: This force acts perpendicular to the surface the cheese is resting on. It is the force exerted by the table on the cheese to support its weight. In this case, since the table is essentially frictionless, the normal force will be equal in magnitude but opposite in direction to the gravitational force.

Therefore, the correct answer is Option a) Gravitational force, applied force, normal force.

User Surui
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