Answer:The answer is b) No.
Explanation:
To determine if the average weight of the packages of cheese is significantly different from the factory's listed weight of 10 oz, we can perform a hypothesis test.
The null hypothesis, denoted as H0, assumes that the average weight of the packages is equal to the listed weight of 10 oz. The alternative hypothesis, denoted as Ha, assumes that the average weight is significantly different from 10 oz.
To conduct the hypothesis test, we need to calculate the standard error of the mean. This can be done by dividing the standard deviation by the square root of the sample size. In this case, the standard deviation is 0.45 oz and the sample size is 5. Therefore, the standard error of the mean is 0.45 / √5 ≈ 0.20 oz.
Next, we can calculate the test statistic, which is the difference between the sample mean and the hypothesized mean (listed weight) divided by the standard error of the mean. The sample mean can be calculated by summing up the weights and dividing by the sample size. In this case, the sample mean is (10.2 + 10.5 + 9.3 + 9.8 + 10.0) / 5 ≈ 10 oz.
The test statistic is therefore (10 - 10) / 0.20 = 0 / 0.20 = 0.
Finally, we compare the test statistic to a critical value based on the desired level of significance. If the test statistic falls within the critical region, we reject the null hypothesis and conclude that the average weight is significantly different from the listed weight. If the test statistic falls outside the critical region, we fail to reject the null hypothesis.
In this case, since the test statistic is 0 and falls within the critical region, we fail to reject the null hypothesis. Therefore, the average weight of the packages of cheese is not significantly different from the factory's listed weight of 10 oz.