Final answer:
To neutralize 0.0164 mol of KOH, we need 0.0082 mol of H2SO4.
Step-by-step explanation:
In order to determine the number of moles of H2SO4 needed to neutralize 0.0164 mol of KOH, we must consider the balanced chemical equation between H2SO4 and KOH:
H2SO4 + 2KOH → K2SO4 + 2H2O
From the equation, we can see that 1 mole of H2SO4 reacts with 2 moles of KOH. Therefore, to neutralize 0.0164 mol of KOH, we would need half as many moles of H2SO4:
Moles of H2SO4 = 0.0164 mol KOH / 2 = 0.0082 mol H2SO4
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