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Write the first three terms of an arithmetic sequence if the fourth term is 10 and D = -6?

User Bizl
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Answer:

First three terms = 28, 22, and 16

Explanation:

The formula for the nth term of an arithmetic sequence is given by:

an = a1 + (n-1)d, where:

  • an is the nth term,
  • a1 is the first term,
  • n is the term position (e.g., 1st, 4th, etc.),
  • and d is the common difference.

Step 1: Find a1:

We can find a1 by substituting 10 for an, 4 for n, and -6 for d in the nth term formula:

10 = a1 + (4 - 1) * -6

10 = a1 + 3 * -6

(10 = a1 - 18) + 18

28 = a1

Thus, the first term is 28.

Step 2: Find a2 (the second term):

Now, we can find the second term by substituting 28 for a1, 2 for n, and -6 for d in the nth term formula:

a2 = 28 + (2 - 1) * -6

a2 = 28 + 1 * -6

a2 = 28 - 6

a2 = 22

Thus, the second term is 22.

Step 3: Find a3 (the third term):

Now, we can find the third term by substituting 28 for a2, 3 for n, and -6 for d in the nth term formula:

a3 = 28 + (3 - 1) * -6

a3 = 28 + 2 * -6

a3 = 28 - 12

a3 = 16

Thus, the third term is 16.

Step 4: Write the first three terms:

Therefore, the first three terms of the arithmetic series are 28, 22, and 16.

User Arienrhod
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