Answer:
Therefore, the probability of a standard normal distribution falling between -0.12 and 1.5 is approximately 0.4810.
Explanation:
To find P(-0.12 < Z < 1.5), where Z represents a standard normal distribution, we need to calculate the probability between these two Z-scores.
Step 1: Look up the Z-scores in the standard normal distribution table.
The Z-score for -0.12 is approximately -0.1249, and the Z-score for 1.5 is 0.9332.
Step 2: Subtract the area to the left of the lower Z-score from the area to the left of the higher Z-score.
P(-0.12 < Z < 1.5) = P(Z < 1.5) - P(Z < -0.12)
From the standard normal distribution table, we find that the area to the left of 1.5 is 0.9332, and the area to the left of -0.12 is 0.4522.
Step 3: Calculate the probability.
P(-0.12 < Z < 1.5) = 0.9332 - 0.4522 = 0.4810