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Suppose that y varies directly as the square root of x, and that y = 28 when x = 16. Find x when y = 49.

User Cheetha
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To solve this problem, you can use the direct variation equation, which relates y and x when y varies directly as the square root of x. The equation can be written as:

y = k√x

Where k is the constant of variation.

Given that y = 28 when x = 16, you can use these values to find the value of k:

28 = k√16

Now, solve for k:

k√16 = 28

k * 4 = 28 (since √16 = 4)

k = 28 / 4

k = 7

Now that you have the value of k, you can use it to find x when y = 49:

49 = 7√x

To isolate x, divide both sides of the equation by 7:

√x = 49 / 7

√x = 7

Now, square both sides to solve for x:

x = (√7)^2

x = 7

So, when y = 49, x = 7.
User MRRaja
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