Final answer:
The lattice energy of SrO calculated using the Born-Haber cycle is 756.9 kJ/mol, which is found by summing the given enthalpies related to the formation of SrO from its elements in their standard states.
Step-by-step explanation:
To calculate the lattice energy of SrO using the Born-Haber cycle, we add the given enthalpies in a stepwise manner. The formula to calculate the lattice energy (AHlattice) is by summing the enthalpy of sublimation, ionization energy, bond dissociation enthalpy, and electronic affinity (if applicable), then subtracting these from the standard enthalpy of formation. In the calculation provided, AHlattice of SrO can be expressed as:
AHlattice = 76.5 kJ/mol (sublimation of Sr) + 79.4 kJ/mol (first ionization energy of Sr) + 375.7 kJ/mol (bond dissociation energy of O2) - 328.2 kJ/mol (electron affinity of O) - (-553.5 kJ/mol) (standard enthalpy of formation of SrO)
Upon adding these values, we obtain:
AHlattice = 756.9 kJ/mol
This means the lattice energy for SrO is estimated to be 756.9 kilojoules per mole. Through this cycle, we can decipher the energy released or required during the formation of an ionic solid from its gaseous ions, which is a fundamental concept in thermodynamics and solid-state chemistry.