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you are blindfolded in a room with eight coins. what is the minimum number of flips required to guarantee that one of the permutations has all coins with the same side?

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2 votes

Answer:

127

Explanation:

You want the minimum number of flips of a coin in a group of 8 coins that will ensure one of the permutations has all coins with the same side.

Permutations

There are 2⁸ = 256 permutations of heads and tails among 8 coins. Half that number, 128, will ensure that 7 of the coins will match the 8th one.

The least number of flips to get from one permutation to another is 1, so 128 -1 = 127 coin flips are necessary to ensure that 7 coins will match the 8th one at some point in the sequence.

127 coin flips are required.

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Additional comment

Suppose we have 3 coins randomly arranged as HTH.

Leaving the first coin alone, it is sufficient to put the last two in every remaining permutation:

HTT, HHT, HHH . . . . result of 3 flips: coin 3, coin 2, coin 3 again

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