Question

How far must a spring with a spring constant of 64N/m be stretched to

store 0.32J of potential energy?

Answer 1

0.1m

Step-by-step explanation:

k = 64N/m

Ep = 0.32J

x = ?

Ep = 1/2 * kx²

make x the subject of the formula

x² = 2Ep/k

x = √(2Ep/k)

x = √(0.64/64)

x = √0.01

x = 0.1m