Question

Find a line containing y-intercept s(0,10) and x-int ecept (2,0)

Answer 1

y = - 5x + 10

Explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate slope m using the slope formula

m =
`(y_(2)-y_(1) )/(x_(2)-x_(1) )`

let (x₁, y₁ ) = (0, 10 ) and (x₂, y₂ ) = (2, 0) ← 2 points on the line

m =
`(0-10)/(2-0)` =
`(-10)/(2)` = - 5

given the y- intercept is (0, 10 ) , then c = 10

y = - 5x + 10 ← equation of line