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(x+4)²=9 x+7=13 Solve 2x²+7x+1=0 using the quadratic formula, Show all work and simplify all radicals.

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Answer:

(x+4)²-9=0

(x+4-3)(x+4+3)= 0

(x+1)(x+7)=0

x+1=0⇔x=-1

x+7=0⇔x=-7

2x²+7x+1=0

b²-4ac= 7²-4(2*1)=41

Δ est strictement positif, l'équation 2x²+7x+1=0 admet deux solutions

(-b-√41)/2a =(-7-√41)/4≈-3,35078...≈3,35

(-b+√√)/2a =(-7+√41)/4≈ -0,1492..=-0,150

x+7-13=0

x-6=0

x=6

Explanation:

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