Question

Which substances are present in the net ionic equation for the reaction that would occur when MgCl2​ (aq) is combined with H3​PO4​(aq) ? [Select all that apply.] A H+(aq) B Cl2−​(aq) C Mg2+(aq) D Mg+(aq) E Mg3​PO4​( s) F Mg3​(PO4​)2​(s) G Mg(aq) Cr (aq) H HCl(aq) MgPO4​ (s) I Mg2​(PO4​)3​ (s) J H3​PO4​(aq)

Answer 1

Answer:the correct options are A (H⁺(aq)) and E (Mg₃(PO₄)₂(s)).

Explanation:To determine which substances are present in the net ionic equation for the reaction between MgCl2(aq) and H3PO4(aq), we first need to write the balanced molecular equation and then separate it into ions to identify the spectator ions. Spectator ions are those ions that do not participate in the chemical reaction and remain unchanged.

First, let's write the balanced molecular equation:

MgCl2(aq) + 2H3PO4(aq) -> Mg3(PO4)2(s) + 6HCl(aq)

Now, let's break down the equation into ions:

Mg²⁺(aq) + 2Cl⁻(aq) + 2H₃PO₄(aq) -> Mg₃(PO₄)₂(s) + 6H⁺(aq) + 6Cl⁻(aq)

Now, let's identify the spectator ions, which are the ions that appear on both sides of the equation and do not change:

- Mg²⁺(aq) is present on both sides.

- Cl⁻(aq) is present on both sides.

So, the spectator ions are Mg²⁺(aq) and Cl⁻(aq).

Now, let's determine the substances that are part of the net ionic equation, excluding the spectator ions:

Net Ionic Equation: 2H₃PO₄(aq) -> Mg₃(PO₄)₂(s) + 6H⁺(aq)

From the net ionic equation, the following substances are present:

A. H⁺(aq)

E. Mg₃(PO₄)₂(s)

So, the correct options are A (H⁺(aq)) and E (Mg₃(PO₄)₂(s)).

The other ions and compounds do not participate directly in the net ionic reaction and are spectator ions.