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Express in terms of sums and differences: logₐ6 x y⁵z⁴

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Answer:

logₐ(6) + logₐ(x) + 5 logₐ(y) + 4 logₐ(z)

Explanation:

Using the properties of logarithms, we can express logₐ6 x y⁵z⁴ in terms of sums and differences as follows:

logₐ6 x y⁵z⁴ = logₐ(6) + logₐ(x) + logₐ(y⁵) + logₐ(z⁴)

= logₐ(6) + logₐ(x) + 5 logₐ(y) + 4 logₐ(z)

This is the final answer.

User Rusev
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