Explanation:
You have given a point (1, -5), a slope of 5, and the line passes through the point (-1, -3). You can use this information to find the equation of the line.
The equation of a line in point-slope form is:
y - y1 = m(x - x1)
Where (x1, y1) is a point on the line, and m is the slope.
Using the given point (1, -5) and the slope m = 5, you can plug these values into the equation:
y - (-5) = 5(x - 1)
Now, simplify:
y + 5 = 5(x - 1)
To put it in slope-intercept form (y = mx + b), expand and solve for y:
y + 5 = 5x - 5
Subtract 5 from both sides:
y = 5x - 5 - 5
y = 5x - 10
So, the equation of the line with a slope of 5 that passes through the point (1, -5) is:
y = 5x - 10