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Variables x,y, and z are integers such that xyz >0. If xy=30,(x)/(z)=(2)/(3), and z=9, what is the value of y ?

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Answer:

y = 5

Explanation:

since z is 9, we can substitute that into x/z = 2/3

x/9 = 2/3

x = 6

next we can substitute it into xy = 30

6y = 30

y=5

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