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Suppose a 250.mL flask is filled with 1.0 mol of H2 and 0.70 mol of HI. The following reaction becomes possible: H₂(g) + I₂(g) ⇌ 2HI(g) The equilibrium constant K for this reaction is 0.467 at the temperature of the flask. I₂,

User Bens
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Final answer:

The equilibrium constant K represents the ratio of the concentrations of the products and the reactants in a chemical reaction at equilibrium. In the given reaction H₂(g) + I₂ (g) ⇌ 2HI(g), one needs to calculate changes in concentrations based on the balanced chemical equation to find equilibrium concentrations.

Step-by-step explanation:

In this scenario, you have a reaction where Hydrogen and Iodine are reacting to form Hydrogen iodide. The relevant chemical reaction is

H₂(g) + I₂ (g) ⇌ 2HI(g)

Firstly, it is crucial to understand that the equilibrium constant K is the ratio of the concentrations of the products and the reactants in a chemical reaction at equilibrium, raised to the power of their stoichiometric coefficients. Here, given K=0.467, it means the concentrations are such that the reaction lies somewhat in favor of the reactants.

The amounts provided (1.0 mol H2 and 0.70 mol HI in a 250mL flask) are the initial number of moles, not necessarily the equilibrium amounts. To find equilibrium concentrations, changes in concentrations need to be calculated based on the balanced chemical equation and these changes applied to the initial amounts to get equilibrium concentrations which can then be put into the equilibrium expression to verify K. For example, if x mol of H2 react, then x mol of I2 will react and 2x mol of HI will be formed.

Learn more about Chemical Equilibrium

User Cong Tran
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