Answer:
I believe the answer is c) 3
Explanation:
f(x) = (x + 3)(x - 1)(2x + 2)
x(x) + x(-1) + 3(x) + 3(-1)
f(x) = (x^2 - x + 3x - 3)(2x + 2)
f(x) = (x^2 + 2x - 3)(2x + 2)
2x(x^2) + 2x(2x) + 2x(-3) + 2(x^2) + 2(2x) + 2(-3)
f(x) = (2x^3 + 4x^2 - 6x + 2x^2 - 6)
f(x) = (2x^3 + 6x^2 - 6x - 6)