Question

At room temperature , 1 mL of water has a mass of 1 gram . What is the percent by mass of a 428 mL magnesium citrate ( solution containing 0.1 mol of magnesium citrate ?

Answer 1

5.0% by mass

Step-by-step explanation:

Percent by mass is 100 times the ratio between the mass of solute (Magnesium citrate) in the mass of solution.

Mass of Magnesium citrate -Molar mass: 214.41g/mol-:

0.1mol * (214.41g/mol) = 21.441g

Assuming the volume of the solution is just due the solvent -Water-, the mass of water is 428g.

Percent by mass is:

21.441g / 428g * 100 =

5.0% by mass