Question

A father divided his property between two sons A and B and one daughterC. The person has Rs. 80000 in cash, Rs. 5 lakhs as land and Rs. 6 lakhsas gold. He gave half of the gold to his daughter and remaining golddivided between sons in equal proportion. He gave only 20% of total landto his daughter and divided the remaining land betiveen sons A and B inthe ratio of 3 : 1 respectively on the condition that the child who receivedhighest share of land will give Rs. 2500 per month to his father. He gave 75% of the total cash amount to his daughter and remaining cash amountwas divided between sons in equal much total property (in cash ,land and gold together)did c get? (A) Rs. 4.9lakhs (B) Rs 4.6 lakhs (C) Rs. 4.7 lakhs (D) Rs. 4.8 lakhsB​

Answer 1

Daughter C received a total of Rs. 4.6 lakhs is property.

Step-by-step explanation:

To find the total amount of property that Daughter C recieved, we need to calculate the amount of cash, land, and gold she got. Let's break it down step by step:

1. Daughter C received 75% of the cash, which is Rs. 60,000 (75% of Rs. 80,000).
2. Daughter C received 20% of the land, which is Rs. 1 lakh (20% of Rs. 5 lakhs).
3. Daughter C received half of the gold, which is Rs. 3 lakhs (half of Rs. 6 lakhs).

Adding up all the amounts Daughter C received:
Cash: Rs. 60,000
Land: Rs. 1 lakh
Gold: Rs. 3 lakhs

The total amount of property Daughter C received is Rs. 4.6 lakhs (Rs. 60,000 + Rs. 1 lakh + Rs. 3 lakhs).

Learn more about Property division