Question

What is the initial velocity of an object which travels a distance of 10t² +15t + 5 along a straight line in time t? a. -10 b. +10 c. -15 d. +15

Answer 1

The initial velocity of the object is +15 m/s.

Step-by-step explanation:

The initial velocity of the object can be found by evaluating the velocity function at t = 0. Given that the distance function is 10t² + 15t + 5, we can find the velocity function by taking the derivative of the distance function with respect to time.

The derivative of 10t² + 15t + 5 is 20t + 15.

Evaluating this expression at t = 0 gives us the initial velocity. Plugging in t = 0 into the velocity function, we get V(0) = 20(0) + 15 = 15 m/s.

Therefore, the initial velocity of the object is +15 m/s, which corresponds to option d.

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