
4 Flashlights
10 Batteries

Let's assume the number of flashlights is "x"
and the number of batteries is "y".
The cost of x flashlights is 6.50x.
The cost of y batteries is 1.50y.
According to the problem, the total cost should be $26.00, so we can write the equation:
6.50x + 1.50y= 26.00
Now, let's find all the possible combinations of x and y that satisfy this equation.
One possible combination is:
- 4 flashlights (x = 4) and 10 batteries (y = 10)
Let's check if this combination satisfies the equation: 6.50(4) + 1.50(10) = 26.00
26.00 + 15.00 = 26.00
26.00
26.00
Since the equation is satisfied, the combination of 4 flashlights and 10 batteries is valid.
Another combination could be:
- 10 flashlights (x = 10) and 4 batteries (y = 4)
Let's check if this combination satisfies the equation: 6.50(10) + 1.50(4) = 26.00
65.00 +6.00 = 26.00
71.00 26.00
Since the equation is not satisfied, the combination of 10 flashlights and 4 batteries
is not valid.
Therefore, the only combination that satisfies the equation and costs exactly $26.00 is 4 flashlights and 10 batteries.