Question

2x = 8y - 2 3x -3y =15

Answer 1

2x=8y-2.....(1)

3x-3y=15.....(2)

2x=8y-2

divide both sides by 2

x=4y-1

substitute for x

3(4y-1)-3y=15

12y-3-3y=15

9y=15+3

9y=18

divide both sides by 9

y=2

substitute y for x

x= 4(2)-1

x=8-1

x=7

Answer 2

x = 7 , y = 2

Explanation:

given the equations

2x = 8y - 2 ( divide through by 2 )

x = 4y - 1 → (1)

3x - 3y = 15 → (2)

substitute x = 4y - 1 into (2)

3(4y - 1) - 3y = 15 ← distribute parenthesis on left side and simplify

12y - 3 - 3y = 15

9y - 3 = 15 ( add 3 to both sides )

9y = 18 ( divide both sides by 9 )

y = 2

substitute y = 2 into (1) and solve for x

x = 4(2) - 1 = 8 - 1 = 7

solution to the system of equations is x = 7 , y = 2