Given:
The figure of a right angle triangle.
![a=b](https://img.qammunity.org/2022/formulas/mathematics/high-school/r9vbsx7xrcjvmeqkfdi4028y2ijfl70h0p.png)
Hypotenuse =
in.
To find:
The missing lengths of the sides.
Solution:
In the given right angle triangle both legs a and b are equal, and hypotenuse is
in.
Using Pythagoras theorem, we get
![Hyponteuse^2=Base^2+Perpendicular^2](https://img.qammunity.org/2022/formulas/mathematics/high-school/qi71pt3pnl9pr0yoyxsriki5z7uutfq0ii.png)
![(9√(2))^2=(a)^2+(b)^2](https://img.qammunity.org/2022/formulas/mathematics/high-school/uxrrm7666zd2ujri1i6jsgsffzz0dwzu0v.png)
![[\because a=b]](https://img.qammunity.org/2022/formulas/mathematics/high-school/9iu9z7nf34819kfzmo8bvrwza1tvw5oyhs.png)
![81(2)=2(a)^2](https://img.qammunity.org/2022/formulas/mathematics/high-school/rci3omzdr66dg2y5lnsaraatmdze11mktt.png)
Divide both sides by 2.
![81=(a)^2](https://img.qammunity.org/2022/formulas/mathematics/high-school/ei1pwqhix1m6nqi0b8fzidxugpn1kamx65.png)
Taking square root on both sides.
![\pm √(81)=a](https://img.qammunity.org/2022/formulas/mathematics/high-school/yb82vfh3g5g23zonlnxcjxpvcjf6eh8x7d.png)
![\pm 9=a](https://img.qammunity.org/2022/formulas/mathematics/high-school/wbf078eo8c1524b46l8bkqkxe1uvwfh6qq.png)
Side cannot be negative. So,
![9=a](https://img.qammunity.org/2022/formulas/mathematics/high-school/oiqwjdzkjnfjthe9pp64mesf72gk38xs6p.png)
Thus, the missing side lengths are a=9 in and b=9 in.
Therefore, the correct option is C.