Step-by-step explanation:
To calculate the amount of heat transferred when two substances at different temperatures are mixed, you can use the formula for heat transfer:
Q = m * c * ΔT
Where:
Q = Heat transferred (in joules)
m = Mass of the substance (in grams or kilograms)
c = Specific heat capacity of the substance (in J/g°C or J/kg°C)
ΔT = Change in temperature (in °C)
First, you need to find the total mass and specific heat capacity for the mixture. Since you have two pots of water:
1. Calculate the total mass:
Mass of first pot = 500 milliliters = 500 grams (1 milliliter of water is approximately 1 gram)
Mass of second pot = 599 grams
Total mass = 500 grams + 599 grams = 1099 grams
2. Water has a specific heat capacity of approximately 4.18 J/g°C.
Now, calculate the change in temperature (ΔT):
ΔT = Final temperature - Initial temperature
The final temperature of the mixture will be somewhere between 3°C and 5°C since you're mixing water at those temperatures. Let's assume it reaches thermal equilibrium at 4°C.
ΔT = 4°C - 4.5°C = -0.5°C
Now, you can calculate the heat transferred (Q):
Q = 1099 grams * 4.18 J/g°C * (-0.5°C) = -2295.77 J (rounded to two decimal places)
So, the amount of heat transferred in the mixing process is approximately -2295.77 joules. The negative sign indicates that heat is lost during the mixing process, which is expected as the warmer water cools down to the equilibrium temperature.