152k views
2 votes
a 500 milliliter pot of water at 3 degrees celsius is mixed with 599 milliliter pot if water at 5 degrees celsius. the amount of heatbis transferred in the mixing process is

User Jetman
by
7.5k points

1 Answer

2 votes

Step-by-step explanation:

To calculate the amount of heat transferred when two substances at different temperatures are mixed, you can use the formula for heat transfer:

Q = m * c * ΔT

Where:

Q = Heat transferred (in joules)

m = Mass of the substance (in grams or kilograms)

c = Specific heat capacity of the substance (in J/g°C or J/kg°C)

ΔT = Change in temperature (in °C)

First, you need to find the total mass and specific heat capacity for the mixture. Since you have two pots of water:

1. Calculate the total mass:

Mass of first pot = 500 milliliters = 500 grams (1 milliliter of water is approximately 1 gram)

Mass of second pot = 599 grams

Total mass = 500 grams + 599 grams = 1099 grams

2. Water has a specific heat capacity of approximately 4.18 J/g°C.

Now, calculate the change in temperature (ΔT):

ΔT = Final temperature - Initial temperature

The final temperature of the mixture will be somewhere between 3°C and 5°C since you're mixing water at those temperatures. Let's assume it reaches thermal equilibrium at 4°C.

ΔT = 4°C - 4.5°C = -0.5°C

Now, you can calculate the heat transferred (Q):

Q = 1099 grams * 4.18 J/g°C * (-0.5°C) = -2295.77 J (rounded to two decimal places)

So, the amount of heat transferred in the mixing process is approximately -2295.77 joules. The negative sign indicates that heat is lost during the mixing process, which is expected as the warmer water cools down to the equilibrium temperature.

User Pierson
by
7.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.