In the case where N = 3, we have three children positioned at equal distances around the circumference of the circle. Each child exerts a force of the same magnitude F on the tire, and we need to calculate the net force on the tire.
To calculate the net force, we can break down each force vector into its x and y components. Since the x-axis is chosen to lie along one of the ropes, we can consider the forces in the x-direction only. The forces in the y-direction will cancel out.
Let's denote the angle between each force vector and the positive x-axis as θ. Since the children are equally spaced, each angle θ will be 120 degrees (360 degrees divided by 3 children).
Now, let's break down each force vector into its x and y components. The x-component of each force can be calculated using cosine, while the y-component can be calculated using sine.
1. Force 1:
- x-component: F * cos(θ)
- y-component: F * sin(θ)
2. Force 2:
- x-component: F * cos(θ)
- y-component: -F * sin(θ) (negative sign because the force is in the opposite direction)
3. Force 3:
- x-component: -2 * F * cos(θ) (negative sign because the force is in the opposite direction)
- y-component: 0 (no y-component since the force is along the x-axis)
To calculate the net force in the x-direction, we add up the x-components of all the forces:
Net force in the x-direction = (F * cos(θ)) + (F * cos(θ)) + (-2 * F * cos(θ))
= 2 * F * cos(θ) - 2 * F * cos(θ)
= 0
Since the net force in the x-direction is zero, we can conclude that the total force on the central tire when N = 3 is zero.
Therefore, the net force on the tire in the case N = 3 is zero.