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How many milliliters of an aqueous solution of 0.151 M potassium iodide is needed to obtain 17.3 grams of the salt? ____ mL You need to make an aqueous solution of 0.152 M manganese(II) iodide for an experiment in lab, using a 300 mL volumetric flask. How much solid manganese(II) iodide should you add? ____ grams

User Flolo
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Answer:

1 ml. 73 g

Step-by-step explanation:

it is not explantation

User Mohamed Elbou
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