Question

provide structures for each compound conststent witn the specuar uata (ii) assign all peaks in the NMR and major absorptions in the IR Note: please draw all structures on this sheet and show your work (Keep the spectra for review) The formuls for this compound is C 10 H 12 O 2 . Solve the structare of thus compound with only the ir and nme spectra. The ir spectrum is deternsined on a nes1 hqquid sanple.

Answer 1

Based on the given formula C10H12O2 and the provided NMR and IR spectra, a possible structure for the compound could be 2-phenylpropanoic acid. The NMR spectrum would show peaks corresponding to the methyl group, aromatic protons, and carboxylic acid proton. The IR spectrum would show a strong absorption peak for the carbonyl group.

Step-by-step explanation:

To determine the structures of compounds based on their spectra, we need to analyze the NMR and IR spectra. The given formula C10H12O2 suggests the presence of 10 carbon atoms, 12 hydrogen atoms, and 2 oxygen atoms. By analyzing the NMR and IR spectra, we can determine the connectivity and functional groups present in the compound, which will help in drawing the structures.

A possible structure for this compound based on the given formula and spectra could be 2-phenylpropanoic acid. The NMR spectrum would show a peak around 2.5-3.0 ppm for the methyl group, a peak around 6.5-7.5 ppm for the aromatic protons, and a peak around 10-12 ppm for the carboxylic acid proton. The IR spectrum would show a strong absorption peak around 1700 cm-1 for the carbonyl group and other characteristic peaks.

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