Question

Subtract. x2+8x3x2+3x−x2+2x−63x2+3x

Answer 1

Explanation:

I did the test.

Answer 2

`(2)/(x)`

Explanation:

Given expression:

`(x^2+8x)/(3x^2+3x)-(x^2+2x-6)/(3x^2+3x)`

As the two fractions have the same denominator, to subtract them, we simply subtract their numerators:

`((x^2+8x)-(x^2+2x-6))/(3x^2+3x)`

Distribute the negative sign:

`(x^2+8x-x^2-2x+6)/(3x^2+3x)`

Simplify the numerator:

`(6x+6)/(3x^2+3x)`

Now, factor both the numerator and the denominator by factoring out the common factor of each:

`(6(x+1))/(3x(x+1))`

Cancel the common factor (x + 1);

`(6)/(3x)`

Finally, divide the numerator and denominator by 3:

`(2)/(x)`