Answer:
D) 146°
Explanation:
remember, the sum of all angles in any triangle is always 180°.
therefore, the angle at B is
180 - angle C - angle D = 180 - 59 - 48 = 73°.
now, the angle at the intersection of 2 chords of a circle is half of the sum of the arc angles in front and in the back of that angle.
in our case, the chords BC and BD intersect at B (directly on the circle arc itself).
so, the arc angle in front of the angle B is y. the arc angle in the back of the angle B is 0.
angle B = ½(y + 0) = y/2
73 = y/2
y = 146°