Question

Given the point slope form of a line equation write in the slope form equation y+1=-3(x-2)

Answer 1

Explanation:

1 Divide both sides by -3−3.

-\frac{y+1}{3}=x-2

−

3

y+1

​

=x−2

2 Add 22 to both sides.

-\frac{y+1}{3}+2=x

−

3

y+1

​

+2=x

3 Regroup terms.

2-\frac{y+1}{3}=x

2−

3

y+1

​

=x

4 Switch sides.

x=2-\frac{y+1}{3}

x=2−

3

y+1

​

Answer 2

Given the line in point slope form:

y + 1 = 3(x - 2)

Let's rewrite the equation in slope intercept form.

Using the point slope form:

y - y1 = m(x - x1)

Thus, we have the following:

x1 = -2

y1 = 1

slope, m = 3

To write in slope intercept form, all you have to do is to isolate the y.

Thus,

y + 1 = 3(x - 2)

Expand the parenthesis:

y + 1 = 3x - 6

Subtract 1 from both sides:

y + 1 - 1 = 3x - 6 - 1

y = 3x - 6 - 1

y = 3x - 7

Therefore, the equation in slope intercept form is:

y = 3x - 7

ANSWER:

y = 3x - 7