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Write a balanced nuclear equation for the decay of mercury-178 by positron emission.

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The decay of mercury-178 (17880Hg) by positron emission involves the emission of a positron (a positively charged electron). Here's the balanced nuclear equation for this decay:

17880Hg -> 17779Au + 0+1e

In this equation:

17880Hg represents the mercury-178 nucleus.

17779Au represents the gold-177 nucleus, which is the result of the decay.

0+1e represents a positron (e+), which is emitted in the process.

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