Question

a solution was formed by combining 50.0 g of solid koh with 200.0 ml of distilled water, with the water initially at 20.4 degrees celsius. the final temperature of the solution was 45.3°C. calculate the qsoln in j, assuming no heat loss to the calorimeter. use 4.184 j g⁻¹ c⁻¹ as the specific heat capacity for water. if your answer is negative, include the negative in your answer. enter your answer to one decimal place.

Answer 1

To calculate the qsoln, use the formula qsoln = (csoln × m × ΔT), where csoln is the specific heat capacity of water (4.184 J/g °C), m is the mass of the solution (200.0 ml of water is approximately 200.0 g), and ΔT is the change in temperature (45.3 °C - 20.4 °C = 24.9 °C). Substituting these values into the formula, we find that qsoln is approximately 20.8 kJ.

Step-by-step explanation:

To calculate the qsoln, we can use the formula qsoln = (csoln × m × ΔT), where csoln is the specific heat capacity of water (4.184 J/g ℃), m is the mass of the solution (200.0 ml of water is approximately 200.0 g), and ΔT is the change in temperature (45.3 ℃ - 20.4 ℃ = 24.9 ℃).

Substituting these values into the formula, we get: qsoln = (4.184 J/g ℃) × (200.0 g) × (24.9 ℃) = 20840 J = 20.8 kJ (rounded to one decimal place).

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