Question

Greg has a vertical velocity of 4 m/s when he leaves the diving board. At this instant, his center of gravity is 4 m above the water. How long will Greg be in the air before he touches the water? Assume that he first touches the water when his center of gravity is 1m above the water. (please include 2 decimal places in your answer)

Answer 1

Greg will be in the air for approximately 1.13 seconds before touching the water.

Step-by-step explanation:

To determine how long Greg will be in the air before touching the water, we can use the kinematic equation for vertical motion. The equation is given as:

y = yo + vot - 1/2gt^2

where y is the final position, yo is the initial position, vo is the initial velocity, g is the acceleration due to gravity, and t is the time. With the given information, we have yo = 4 m, vo = 4 m/s, and y = 1 m. Plugging these values into the equation, we get:

1 = 4 + 4t - 1/2(9.8)t^2

Simplifying the equation and solving for t, we find that Greg will be in the air for approximately 1.13 seconds before touching the water.

Learn more about vertical motion