140k views
1 vote
What volume, in milliliters, of 0.410 m ca(oh)2 is needed to completely neutralize 221 ml of a 0.280 m hi solution?

1 Answer

4 votes

Final answer:

To neutralize the HI solution, we can use the balanced equation and stoichiometric ratio to determine the volume of Ca(OH)2 needed.

Step-by-step explanation:

To find the volume of 0.410 M Ca(OH)2 needed to neutralize 221 mL of a 0.280 M HI solution, we can use the balanced equation between Ca(OH)2 and HI:

Ca(OH)2 + 2HI → CaI2 + 2H2O

The stoichiometric ratio between Ca(OH)2 and HI is 1:2. This means that for every mole of Ca(OH)2, we need 2 moles of HI. Using the given concentrations and volumes, we can calculate the amount of HI reacted and from there determine the volume of Ca(OH)2 needed.

Learn more about Neutralization reaction

User EnaJ
by
7.3k points