Question

What is the initial temperature of a 250. gram piece of iron (specific heat of iron is 0.449 j/g oc) that has lost 1450 j of heat and cooled to 23.0 oc?

Answer 1

The initial temperature of the iron piece is 239.22°C.

Step-by-step explanation:

To find the initial temperature of the iron piece, we need to use the formula:

Q = mcΔT

Where:

- Q is the heat lost/gained by the substance (in this case, -1450 J as it lost heat)

- m is the mass of the substance (250 g)

- c is the specific heat of the substance (0.449 J/g°C)

- ΔT is the change in temperature of the substance (final temperature - initial temperature, in this case, 23.0°C - initial temperature)

Plugging in the values:

-1450 J = (250 g)(0.449 J/g°C)(23.0 - initial temperature)

Simplifying the equation:

1450 J = 112.25 g°C - (5.596 g°C * initial temperature)

Now we can solve for the initial temperature:

112.25 g°C - 1450 J = -5.596 g°C * initial temperature

1337.75 J = 5.596 g°C * initial temperature

initial temperature = 1337.75 J / (5.596 g°C) = 239.22°C

Learn more about Specific heat capacity