Question

In 2015 629,647 patients were applied for and 325,979 of them were accepted to the nearest 10th of a percent what percentage of the patient were accepted

Answer 1

Explanation:

We are given that the total number of patients who were applied for is 629,647. This is all of the patients accounted for -- or, it is the whole.

We are also given that out of these 629,647 patients, 325,979 of them were accepted. 325,979 is a part of the whole (which is 629,647).

In order to find the percentage of patients that were accepted, we will set up a fraction that looks like this:

patients accepted/total patients

This fraction tells us what portion of the total patients were accepted. by replacing the values, we get:

`(325,979)/(629,647 )`

To find the percentage, let's set up a proportion so that 325,979/629,647 is proportionate to a number x over 100 (recall that percentages can be represented using fractions by having a number over 100. For example, 96% is 96/100, 4% is 4/100, etc.)

Our proportion will look like this:

`(325,979)/(629,647 )=(x)/(100)`

We can multiply the means and extremes here (the means being 629,647 and x, the extremes being 325,979 and 100) in order to solve our proportion, like so:

`629,647*x=325,979 *100=629,647x = 32,597,900`

After dividing 32,597,900 by 629,647, we get that x≈51.771707. After rounding 51.771707 to the nearest tenth, we will get 51.8.

Thus, about 51.8% of the patients were accepted.

Answer 2

Out of 629,647 patients who applied in 2015, 325,979 were accepted. To calculate the percentage of patients who were accepted, we can divide the number of accepted patients by the total number of patients who applied and then multiply the result by 100.

So, (325,979 / 629,647) x 100 = 51.8%

Therefore, approximately 51.8% of the patients who applied in 2015 were accepted.