Answer:
To solve the quadratic equation x^2 + 6x + 7 = 0, we can use the quadratic formula:
x = (-b ± √(b² - 4ac)) / (2a)
In this equation:
a = 1 (coefficient of x²)
b = 6 (coefficient of x)
c = 7 (constant term)
Now, plug these values into the formula:
x = (-6 ± √(6² - 4 * 1 * 7)) / (2 * 1)
x = (-6 ± √(36 - 28)) / 2
x = (-6 ± √8) / 2
Now, simplify further:
x = (-6 ± 2√2) / 2
We can simplify the fraction by dividing both the numerator and denominator by 2:
x = (-3 ± √2)
So, the solutions to the quadratic equation x^2 + 6x + 7 = 0 are:
x = -3 + √2 (this is one solution)
x = -3 - √2 (this is the other solution)
Explanation:
So, the correct answer is option (c):
x = -3 plus or minus the square root of 2.