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Find the equation of the line passing through the points (4,2) and (6,10)

User Sumnulu
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1 Answer

3 votes

Answer:

y = 4x - 14

Explanation:

Given two points that lie on a line, we can find the line's equation passing through the points in slope-intercept form, whose general equation is given by:

y = mx + b, where:

  • m is the slope,
  • and b is the y-intercept.

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Finding the slope (m):

We can find the slope of the line using the slope formula, which is given by:

m =(y2 - y1) / (x2 - x1), where:

  • m is the slope,
  • (x1, y1) is one point on the line,
  • and (x2, y2) is another point.

Thus, we can find the slope by substituting (4, 2) for (x1, y1) and (6, 10) for (x2, y2) in the slope formula:

m = (10 - 2) / (6 - 4)

m = 8 / 2

m = 4

Thus, the slope of the line is 4.

Finding the y-intercept (b):

Now we can find the y-intercept by substituting (4, 2) for (x, y) and 4 for m in the general equation of the slope-intercept form:

2 = 4(4) + b

(2 = 16 + b) - 16

-14 = b

Thus, the y-intercept of the line is -14.

Writing the equation of the line in slope-intercept form (y = mx + b):

Therefore, y = 4x - 14 is the equation of the line passing through the points (4, 2) and (6, 10)

User Neda
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