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5427Co →?+0+1e Express your answer as a nuclear symbol.

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The expression you've provided, "5427Co →?+0+1e," appears to represent the decay of a cobalt-54 (5427Co) nucleus. In this decay, a cobalt-54 nucleus transforms into another element through beta decay. Beta decay involves the emission of a beta particle, which is an electron (0-1e).

The resulting nuclear symbol can be written as follows:

5427Co -> 5527Co + 0-1e

This represents the transformation of cobalt-54 (5427Co) into cobalt-55 (5527Co) with the emission of a beta particle (0-1e), which is an electron.

User Pankaj Singh
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