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A reaction takes place in various steps. The rate constant for first, second, third and fifth steps are respectively. The overall rate constant is given by k1,k2,k3, and k5 k= k2​/k3 [K1/k5]​¹/² If activation energy is 40,60,50 and 10 kJ/mol respectively, the overall energy of activation (kJ/mol) is : A 10 B 20 C 25 D none of these Hard

User Nehem
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Final answer:

The overall energy of activation of a reaction is determined based on the activation energies of each step in the reaction and the sequence of these steps. This is related to the Arrhenius equation, which relates the temperature and rate constant of a reaction to its activation energy. Without additional specific information on the nature of the reaction, an exact numerical response can't be provided.

Step-by-step explanation:

The calculation of overall energy of activation involves understanding the application of Activation Energy and the Arrhenius Equation which describes how the rate constant (k), which we know varies with the temperature of the reaction, is related to the activation energy (Ea) of a reaction. In this context, the activation energy is the minimum energy needed for a reaction to occur. It is represented by the Arrhenius equation: k = Ae^-Ea/RT where A is the frequency factor (related to frequency of collisions and orientation of reacting molecules), Ea is the activation energy in joules per mole, R is the ideal gas constant (8.314 J/mol/K), and T is the temperature on the Kelvin scale.

If the provided activation energies are 40, 60, 50, and 10 kJ/mol, the exact combination and sequence of these energy levels in the reaction determine the overall activation energy. The selection of these energies and the sequence of steps is potentially critical to the overall reaction rate due to the energy profile of the reaction. The specific answer to this question could potentially vary based on the type of reaction and exact conditions, and additional details may be needed to provide an exact numerical response.

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User Qwertzguy
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