Question

A stone is thrown vertically upward with the speed of 20m/s .How high will it goes before it begins to fall . (g=9.8 m/s²)

Answer 1

The stone will go approximately 20.4 meters high before it begins to fall.

Step-by-step explanation:

Given that a stone is thrown vertically upward with a speed of 20 m/s and the acceleration due to gravity is 9.8 m/s², we can determine the height it reaches before it begins to fall using kinematic equations.

Let's assume the initial velocity is positive when thrown upward and negative when falling downward.

Using the equation v² = u² + 2as, where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the distance or change in position, we can plug in the known values to solve for the height:

v = 0 m/s (when the stone reaches its maximum height)

u = 20 m/s (initial velocity)

a = -9.8 m/s² (acceleration due to gravity)

s = ? (height we want to find)

0² = 20² + 2(-9.8)s

s = (20²)/(2(9.8))

s ≈ 20.4 meters

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