Question

the weight of an object is 5N. At a certain instant its momentum is 6kgms-1. Due to a force applied in the direction opposite to the direction of motion the velocity is of the object decreased to 4ms-1 during 4s. what is the force exerted on the object?

Answer 1

To find the force exerted on the object, we need to calculate the change in momentum and the acceleration. The force exerted on the object is -0.75 N in the opposite direction to its motion.

Step-by-step explanation:

To find the force exerted on the object, we need to first calculate the change in momentum. The initial momentum of the object is 6 kg·m/s, and the final momentum is calculated using the formula:

Final momentum = mass × Final velocity

Substituting the values, we get:

6 kg·m/s = mass × 4 m/s

Simplifying the equation gives us the mass of the object, which is 1.5 kg. Now we can use the formula for force:

Force = mass × acceleration

The acceleration can be calculated by dividing the change in velocity by the time it takes, which gives:

Acceleration = (4 m/s - 6 m/s) / 4 s = -0.5 m/s²

Finally, substituting the values into the formula gives the force exerted on the object:

Force = 1.5 kg × (-0.5 m/s²) = -0.75 N

Since the force is in the opposite direction to the motion, the force exerted on the object is 0.75 N in the direction opposite to its motion.

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