Step-by-step explanation:
To calculate the horizontal force required to give a 1300 kg vehicle an acceleration of 2.6 m/s^2 on a level road, you can use Newton's second law of motion, which states:
\[F = m \cdot a\]
Where:
- \(F\) is the force (in Newtons, N)
- \(m\) is the mass of the vehicle (in kilograms, kg)
- \(a\) is the acceleration (in meters per second squared, m/s^2)
In this case, the mass of the vehicle (\(m\)) is 1300 kg, and the acceleration (\(a\)) is 2.6 m/s^2. Plug these values into the formula:
\[F = 1300 \, \text{kg} \times 2.6 \, \text{m/s}^2\]
Now, calculate the force:
\[F = 3380 \, \text{N}\]
So, a horizontal force of 3380 Newtons must be applied to the 1300 kg vehicle to give it an acceleration of 2.6 m/s^2 on a level road.