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What is the equation of the line that passes through (4, -1) and (-2, 3)?

User Larue
by
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2 Answers

8 votes

Answer:

3--1/-2-4=4/-6=2/-3

y=-2/3x+b

-2*-2/3=4/3

3-4/3=5/3

y=-2/3x+5/3

Explanation:

User Yasuyo
by
7.9k points
11 votes

Answer:


\displaystyle y=-(2)/(3)x+(5)/(3)

Explanation:

We want to find the equation of the line that passes through the two points:

(4, -1) and (-2, 3).

First, we will find the slope of the two points. So:


\displaystyle m=(3-(-1))/(-2-4)=(4)/(-6)=-(2)/(3)

Now, we will use the point-slope form given by:


y-y_1=m(x-x_1)

Use either point. I'm going to use (4, -1). So, substitute:


\displaystyle y-(-1)=-(2)/(3)(x-(4))

Simplify and distribute:


\displaystyle y+1=-(2)/(3)x+(8)/(3)

Subtract 1 from both sides. Therefore:


\displaystyle y=-(2)/(3)x+(5)/(3)

User Wstk
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