Question

Solve each equation with the quadratic formula. 12a^2+2=0

Answer 1

`\sf x = (\± √(6))/(6)`

Explanation:

We can solve a quadratic equation using quadratic formula.

12a² + 2 = 0

a = coefficient of x² = 12

b = coefficient of x = 0

c = constant = 2

`\boxed{\bf x = (-b \± √(b^2 - 4ac))/(2a)}`

b² - 4ac = 0 - 4*12*2

= -96 < 0

So, roots are complex numbers.

`\sf x = (0 \± √(-96))/(2*12)\\\\\\x = (\±4i√(6) )/(24)\\\\\\x = ( \±i√(6))/(6)`

Answer:

`\sf x = ( \± i√(6))/(6)`