Question

you have two dice: one has 2 threes, 2 fours, and 2 sixes, and the other has 5 ones and 1 five. you roll both dice. what is the expected value of the sum of the two faces?

Answer 1

HI,

Explanation:

Dice 1: 3,3,4,4,6,6

p(x=3)=1/3

p(x=4)=1/3

p(x=6)=1/3

Dice 2: 1,1,1,1,1,5

p(x=1)=5/6

p(x=4)=1/6

Probability of the sum :

p(x=3+1=4)=1/3*5/6=5/18

p(x=4+1=5)=1/3*5/6=5/18

p(x=6+1=7)=1/3*5/6=5/18

p(x=3+5=8)=1/3*1/6=1/18

p(x=4+5=9)=1/3*1/6=1/18

p(x=6+5=11)=1/3*1/6=1/18